Difference between revisions of "Interview Preparation Pointers"
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Pointer 1809844068 | Pointer 1809844068 | ||
Pointer 20 | Pointer 20 | ||
+ | </pre> | ||
+ | |||
+ | '''Malloc''' | ||
+ | |||
+ | The Malloc function dynamically allocates memory when required. The function allocates size of byte of memory and returns a pointer to the first byte of NULL. | ||
+ | |||
+ | <pre> | ||
+ | Syntax: | ||
+ | pointer = (type)malloc(size in bytes); | ||
+ | |||
+ | Code: | ||
+ | |||
+ | int* p; //Declare pointer | ||
+ | p = (int*)malloc(sizeof(int)); // Pointer equal to pointer type int that contain memory address space of int | ||
+ | *p = 5; // Finally pointer points to location containing value 5 | ||
+ | </pre> | ||
+ | |||
+ | '''Pointer to Pointer''' | ||
+ | We have pointer to int, when we have a pointer to pointer , our new pointer (n_ptr in this case) contains the address of the pointer (ptr in this case), which in turn points to the int variable. | ||
+ | |||
+ | <pre> | ||
+ | Code : | ||
+ | #include <stdio.h> | ||
+ | |||
+ | int main () { | ||
+ | int i; | ||
+ | int *ptr; | ||
+ | int **n_ptr; | ||
+ | |||
+ | i = 5; | ||
+ | /* take the address of var */ | ||
+ | ptr = &i; | ||
+ | |||
+ | /* take the address of ptr using address of operator & */ | ||
+ | n_ptr = &ptr; | ||
+ | |||
+ | /* take the value using pptr */ | ||
+ | printf("Value of i = %d\n", i ); | ||
+ | printf("Address of i = %d\n", &i ); | ||
+ | printf("Value available at *ptr = %d\n", *ptr ); | ||
+ | printf("Value available at ptr = %d\n", ptr ); | ||
+ | printf("Address available of ptr = %d\n", &ptr ); | ||
+ | printf("Value available at **n_ptr = %d\n", **n_ptr); | ||
+ | printf("Value available in n_ptr = %d\n", n_ptr); | ||
+ | printf("Value available in *n_ptr = %d\n", *n_ptr); | ||
+ | return 0; | ||
+ | } | ||
+ | |||
+ | Output : | ||
+ | |||
+ | Value of i = 5 | ||
+ | Address of i = -1539864 | ||
+ | Value available at *ptr = 5 | ||
+ | Value available at ptr = -1539864 | ||
+ | Address available of ptr = -1539860 | ||
+ | Value available at **n_ptr = 5 | ||
+ | Value available in *n_ptr = -1539864 | ||
+ | Value available in n_ptr = -1539860 | ||
+ | </pre> | ||
+ | |||
+ | |||
+ | '''Passing Pointers to a Function''' | ||
+ | In the code below we have a defines a function values , which return void . It takes two parameters which are pointers to an integer. When the function is called the address of the integer is passed and not the value . | ||
+ | |||
+ | <pre> | ||
+ | Code: | ||
+ | |||
+ | #include <stdio.h> | ||
+ | |||
+ | /* function declaration */ | ||
+ | void value(int *num_ptr_1, int *num_ptr_2); | ||
+ | |||
+ | int main () { | ||
+ | |||
+ | /* local variable definition */ | ||
+ | int a = 100; | ||
+ | int b = 200; | ||
+ | |||
+ | /* calling a function value */ | ||
+ | value(&a, &b); | ||
+ | |||
+ | return 0; | ||
+ | } | ||
+ | |||
+ | /* function prints the value of two numbers */ | ||
+ | void value(int *num1, int *num2) { | ||
+ | |||
+ | printf("The value of num1 is %d & num2 is %d", *num1 , *num2 ); | ||
+ | |||
+ | } | ||
+ | |||
+ | Output : | ||
+ | |||
+ | The value of num1 is 100 & num2 is 200 | ||
+ | </pre> | ||
+ | |||
+ | |||
+ | '''Passing Pointer from a function''' | ||
+ | In the example below returning the address of the local variable outside a function is not a good idea , hence we declare the variable as static . | ||
+ | |||
+ | <pre> | ||
+ | Code: | ||
+ | #include <stdio.h> | ||
+ | |||
+ | /* function return max number. */ | ||
+ | int* getMax( ) { | ||
+ | |||
+ | static int a = 100; | ||
+ | static int b = 200; | ||
+ | |||
+ | if (a > b) | ||
+ | { | ||
+ | return &a; | ||
+ | } | ||
+ | else | ||
+ | { | ||
+ | return &b; | ||
+ | } | ||
+ | } | ||
+ | |||
+ | /* main function to call above defined function */ | ||
+ | int main () { | ||
+ | |||
+ | /* a pointer to an int */ | ||
+ | int *p; | ||
+ | |||
+ | p = getMax(); | ||
+ | printf("The Max value is %d\n", *p); | ||
+ | |||
+ | return 0; | ||
+ | } | ||
+ | |||
+ | Output : | ||
+ | |||
+ | The Max value is 200 | ||
+ | </pre> | ||
+ | |||
+ | |||
+ | '''Array of Pointers''' | ||
+ | There can be a situation where we have to maintain array , which stores pointers to int or char or any-other datatype. This can be done as follows. | ||
+ | |||
+ | <pre> | ||
+ | Code : | ||
+ | |||
+ | #include <stdio.h> | ||
+ | |||
+ | int main () { | ||
+ | |||
+ | int var[] = {10, 100, 200}; | ||
+ | int i = 0, *ptr = var; | ||
+ | |||
+ | /* Print the values of array var */ | ||
+ | printf("Value of var[%d] = %d\n", i++, *(ptr++) ); | ||
+ | printf("Value of var[%d] = %d\n", i++, *(ptr++) ); | ||
+ | printf("Value of var[%d] = %d\n", i, *ptr ); | ||
+ | return 0; | ||
+ | } | ||
+ | |||
+ | Output : | ||
+ | Value of var[0] = 10 | ||
+ | Value of var[1] = 100 | ||
+ | Value of var[2] = 200 | ||
</pre> | </pre> |
Latest revision as of 19:07, 18 December 2016
Pointers : A pointer is a variable who's value is address of some other variable i.e. it can be address of some memory location.
<varaible_type> *<name> eg : int *pointer_to_integer
The above example , we have declared a pointer to a variable (pointer_to_integer), the variable stores the address of an integer .
Implementation of Pointer :
Code: #include <stdio.h> int main(void) { int var = 20; int *p; p = &var; printf("Pointer %d\n",var); printf("Pointer %d\n",&var); // Prints the address of the varaible (var) printf("Pointer %d\n",p); printf("Pointer %d\n",*p); // Prints the value that (p) points to return 0; } Output : Pointer 20 Pointer 1809844068 Pointer 1809844068 Pointer 20
Malloc
The Malloc function dynamically allocates memory when required. The function allocates size of byte of memory and returns a pointer to the first byte of NULL.
Syntax: pointer = (type)malloc(size in bytes); Code: int* p; //Declare pointer p = (int*)malloc(sizeof(int)); // Pointer equal to pointer type int that contain memory address space of int *p = 5; // Finally pointer points to location containing value 5
Pointer to Pointer
We have pointer to int, when we have a pointer to pointer , our new pointer (n_ptr in this case) contains the address of the pointer (ptr in this case), which in turn points to the int variable.
Code : #include <stdio.h> int main () { int i; int *ptr; int **n_ptr; i = 5; /* take the address of var */ ptr = &i; /* take the address of ptr using address of operator & */ n_ptr = &ptr; /* take the value using pptr */ printf("Value of i = %d\n", i ); printf("Address of i = %d\n", &i ); printf("Value available at *ptr = %d\n", *ptr ); printf("Value available at ptr = %d\n", ptr ); printf("Address available of ptr = %d\n", &ptr ); printf("Value available at **n_ptr = %d\n", **n_ptr); printf("Value available in n_ptr = %d\n", n_ptr); printf("Value available in *n_ptr = %d\n", *n_ptr); return 0; } Output : Value of i = 5 Address of i = -1539864 Value available at *ptr = 5 Value available at ptr = -1539864 Address available of ptr = -1539860 Value available at **n_ptr = 5 Value available in *n_ptr = -1539864 Value available in n_ptr = -1539860
Passing Pointers to a Function
In the code below we have a defines a function values , which return void . It takes two parameters which are pointers to an integer. When the function is called the address of the integer is passed and not the value .
Code: #include <stdio.h> /* function declaration */ void value(int *num_ptr_1, int *num_ptr_2); int main () { /* local variable definition */ int a = 100; int b = 200; /* calling a function value */ value(&a, &b); return 0; } /* function prints the value of two numbers */ void value(int *num1, int *num2) { printf("The value of num1 is %d & num2 is %d", *num1 , *num2 ); } Output : The value of num1 is 100 & num2 is 200
Passing Pointer from a function
In the example below returning the address of the local variable outside a function is not a good idea , hence we declare the variable as static .
Code: #include <stdio.h> /* function return max number. */ int* getMax( ) { static int a = 100; static int b = 200; if (a > b) { return &a; } else { return &b; } } /* main function to call above defined function */ int main () { /* a pointer to an int */ int *p; p = getMax(); printf("The Max value is %d\n", *p); return 0; } Output : The Max value is 200
Array of Pointers
There can be a situation where we have to maintain array , which stores pointers to int or char or any-other datatype. This can be done as follows.
Code : #include <stdio.h> int main () { int var[] = {10, 100, 200}; int i = 0, *ptr = var; /* Print the values of array var */ printf("Value of var[%d] = %d\n", i++, *(ptr++) ); printf("Value of var[%d] = %d\n", i++, *(ptr++) ); printf("Value of var[%d] = %d\n", i, *ptr ); return 0; } Output : Value of var[0] = 10 Value of var[1] = 100 Value of var[2] = 200