Difference between revisions of "Interview Preparation Linked List"
Proj user10 (talk | contribs) (→Singly Linked List) |
Proj user4 (talk | contribs) (→Loop in the List) |
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=== List Reversal === | === List Reversal === | ||
<syntaxhighlight lang="c"> | <syntaxhighlight lang="c"> | ||
+ | |||
#include <stdlib.h> /* malloc() */ | #include <stdlib.h> /* malloc() */ | ||
Line 92: | Line 93: | ||
void ll_reverse(linked_list_t** data) | void ll_reverse(linked_list_t** data) | ||
{ | { | ||
− | linked_list_t* prev = NULL; | + | linked_list_t* prev = NULL; /*previous node is made NULL*/ |
− | linked_list_t* g_head= *data; | + | linked_list_t* g_head= *data; /*data is assigned to head node*/ |
linked_list_t* next; | linked_list_t* next; | ||
while (g_head) | while (g_head) | ||
{ | { | ||
− | next = g_head->next; | + | next = g_head->next; |
g_head->next = prev; | g_head->next = prev; | ||
prev = g_head; | prev = g_head; | ||
Line 108: | Line 109: | ||
<BR/> | <BR/> | ||
+ | |||
=== Loop in the List=== | === Loop in the List=== | ||
<syntaxhighlight lang="c"> | <syntaxhighlight lang="c"> | ||
#include <stdlib.h> /* malloc() */ | #include <stdlib.h> /* malloc() */ | ||
− | /*Function to | + | /*Function to detect a loop in a singly linked list by iterating through the list by using two pointers |
+ | Slow pointer -> steps through each node | ||
+ | Fast pointer -> Skips every other node | ||
+ | */ | ||
bool ll_loop(linked_list_t* head) | bool ll_loop(linked_list_t* head) | ||
{ | { | ||
Line 143: | Line 148: | ||
− | void remove_dups(linked_list_t* head){ | + | void remove_dups(linked_list_t* head){ //we are never deleting the head node |
linked_list_t* current = head; //current node | linked_list_t* current = head; //current node | ||
linked_list_t *pointer1, *duplicate; | linked_list_t *pointer1, *duplicate; | ||
− | while(current->next != NULL){// | + | while(current->next != NULL){//traversing the list pointed by current |
pointer1 = current;// the current node is copied into pointer1 | pointer1 = current;// the current node is copied into pointer1 | ||
− | while( | + | while(pointer1->next != NULL){// traversing the list pointed by pointer1 |
if(pointer1->next->data == current->data){ //Checking for duplicates by comparing the current data and pointer1 data of next node | if(pointer1->next->data == current->data){ //Checking for duplicates by comparing the current data and pointer1 data of next node | ||
duplicate = pointer1->next;// copy the address of pointer1 node (which contains duplicate data) into duplicate | duplicate = pointer1->next;// copy the address of pointer1 node (which contains duplicate data) into duplicate | ||
pointer1->next = pointer1->next->next;//placing the new address i.e. the next node address into pointer to which it will be pointing next | pointer1->next = pointer1->next->next;//placing the new address i.e. the next node address into pointer to which it will be pointing next | ||
− | free( | + | free(duplicate);//free the duplicate node (which contains duplicate data) |
} | } | ||
− | + | pointer1 = pointer1->next;//move to the next node | |
− | pointer1 = pointer1->next;// | ||
} | } | ||
current = current->next;//current pointing to next node | current = current->next;//current pointing to next node | ||
Line 180: | Line 184: | ||
bool isPalindrome(linked_list_t *head){ | bool isPalindrome(linked_list_t *head){ | ||
− | linked_list_t *reverse = reverse(head); | + | linked_list_t *reverse = reverse(head);// calling function to reverse the list |
− | return checkPalindrome(head,reverse); | + | return checkPalindrome(head,reverse);// calling function to check if the list is Palindrome |
} | } | ||
Line 188: | Line 192: | ||
while(head1->next != NULL){ | while(head1->next != NULL){ | ||
− | linked_list_t *new_reverse_node = (linked_list_t*)malloc(sizeof(linked_list_t)); | + | linked_list_t *new_reverse_node = (linked_list_t*)malloc(sizeof(linked_list_t));// new node create to copy the current list in reverse order |
− | new_reverse_node->data = head1->data; | + | new_reverse_node->data = head1->data;// copy head data into new node |
− | new_reverse_node->next = temp; | + | new_reverse_node->next = temp;//reversing the list by making the first node the last node |
temp = new_reverse_node; | temp = new_reverse_node; | ||
− | head1 = head1->next; | + | head1 = head1->next;//traverse till the end of the list |
} | } | ||
return temp; | return temp; | ||
Line 215: | Line 219: | ||
== Doubly Linked List == | == Doubly Linked List == | ||
Let's elaborate on our linked list such that we have the '''next''' and the '''previous''' links. We will have the added benefit of going backwards from an element at the cost of the memory requirement of an extra pointer along with more code to deal with this extra pointer. | Let's elaborate on our linked list such that we have the '''next''' and the '''previous''' links. We will have the added benefit of going backwards from an element at the cost of the memory requirement of an extra pointer along with more code to deal with this extra pointer. | ||
+ | <syntaxhighlight lang="c"> | ||
+ | typedef struct linked_list_node { | ||
+ | struct linked_list_node *next; /*next node*/ | ||
+ | struct linked_list_node* prev; /*previous node*/ | ||
+ | int data; | ||
+ | } linked_list_t; | ||
+ | |||
+ | /* Assume this is a source file, such as linked_list.c */ | ||
+ | /* g for "global" variable of this file, and static for "private variable" of this file */ | ||
− | + | static linked_list_t *g_head = NULL; | |
+ | |||
+ | /*new node is created and a pointer is returned */ | ||
+ | |||
+ | linked_list_t *create_new_node(int n ) { | ||
+ | linked_list_t *new_node | ||
+ | = malloc(sizeof(linked_list_t)); /*creating a new node*/ | ||
+ | new_node->data = n; /*assigning input to data*/ | ||
+ | new_node->prev = NULL; /*previous and next links are initialized to NULL*/ | ||
+ | new_node->next = NULL; | ||
+ | return new_node; /*returning a pointer*/ | ||
+ | } | ||
+ | |||
+ | /*Inserting node at head */ | ||
+ | void insert_at_head(int n) { | ||
+ | linked_list_t* new_node = create_new_node(n); /*creating a new node*/ | ||
+ | |||
+ | if(g_head == NULL) { /*condition to check if the head node is empty*/ | ||
+ | g_head = new_node; | ||
+ | return; | ||
+ | } | ||
+ | |||
+ | g_head->prev = new_node; /*assigning new node to head node */ | ||
+ | new_node->next = g_head; | ||
+ | g_head = new_node; | ||
+ | } | ||
+ | |||
+ | /*to insert a node at tail*/ | ||
+ | void insert_at_tail(int n) { | ||
+ | linked_list_t* temp = g_head; | ||
+ | linked_list_t* new_node = create_new_node(n); //creating a new node | ||
+ | |||
+ | if(g_head == NULL) { | ||
+ | g_head = new_node; | ||
+ | return; | ||
+ | } | ||
+ | |||
+ | while(temp->next != NULL) temp = temp->next; //last node | ||
+ | temp->next = new_node; | ||
+ | new_node->prev = temp; | ||
+ | } | ||
+ | |||
+ | |||
+ | </syntaxhighlight> | ||
+ | <BR/> | ||
+ | |||
+ | == Delete a node in a linked list== | ||
+ | <syntaxhighlight lang="c"> | ||
+ | typedef struct linked_list_node { | ||
+ | struct linked_list_node *next; /*next node*/ | ||
+ | int data; | ||
+ | } linked_list_t; | ||
+ | |||
+ | void delete_node(linked_list_t *g_head, linked_list_t *N) | ||
+ | { | ||
+ | /* to delete head node */ | ||
+ | if(g_head == N) | ||
+ | { | ||
+ | if(g_head->next == NULL) | ||
+ | { | ||
+ | return; | ||
+ | } | ||
+ | |||
+ | /* Copy next node data to head node */ | ||
+ | g_head->data = g_head->next->data; | ||
+ | |||
+ | /* copy address of next node to N*/ | ||
+ | N = g_head->next; | ||
+ | |||
+ | /* delete next node */ | ||
+ | g_head->next = g_head->next->next; | ||
+ | |||
+ | free(N); | ||
+ | return; | ||
+ | } | ||
+ | |||
+ | /* to delete a node other than the first(head) node */ | ||
+ | /*previous node */ | ||
+ | linked_list_t *prev = g_head; | ||
+ | while(prev->next != NULL && prev->next != N) | ||
+ | prev = prev->next; | ||
+ | |||
+ | /*check if prev node exists */ | ||
+ | if(prev->next == NULL) | ||
+ | { | ||
+ | return; | ||
+ | } | ||
+ | |||
+ | /*Delete that node from Linked List | ||
+ | prev->next = prev->next->next; | ||
+ | |||
+ | free(N); | ||
+ | |||
+ | return; | ||
+ | } | ||
+ | </syntaxhighlight> | ||
+ | <BR/> | ||
+ | |||
+ | == Make List unique using STL and recursion == | ||
+ | The task - given a list of '''''n''''' integers in a list, remove all the duplicate values so that what remains is a list of unique values. | ||
+ | <br> | ||
+ | This example exclusively makes use of STL Library '''''<list>''''' and '''''recursion'''''. | ||
+ | <br> | ||
+ | '''''Approach:''''' First define function '''''member_of''''' that checks if a value '''''x'''''' is present in the list. | ||
+ | <syntaxhighlight lang="c"> | ||
+ | bool member_of(const int value, const list<int>& my_list, list<int>::const_iterator it) | ||
+ | { | ||
+ | if (it == my_list.end()) | ||
+ | return false; | ||
+ | return (*it == value) || member_of(value, my_list, ++it); | ||
+ | } | ||
+ | </syntaxhighlight> | ||
+ | <br> | ||
+ | Now, take out the first value. Make the rest of the list unique. Then if the value we took out is not in the rest of the list, put it back. Otherwise, leave it out. | ||
+ | <br> | ||
+ | <syntaxhighlight lang="c"> | ||
+ | void isListUnique(list<int>& alist) | ||
+ | { | ||
+ | if (alist.size() <= 1) return; // base case | ||
+ | |||
+ | int first = alist.front(); | ||
+ | alist.erase(alist.begin()); // remove the first element | ||
+ | |||
+ | isListUnique(alist); // make the rest of the list unique | ||
+ | |||
+ | if (!member_of(first, alist, alist.begin())) | ||
+ | { | ||
+ | alist.push_front(first); // put back the first element | ||
+ | } | ||
+ | } | ||
+ | </syntaxhighlight> | ||
+ | <BR/> | ||
+ | == Reverse a linked list using STL and recursion == | ||
+ | '''''Task -''''' Reverse the values of a list of '''''n''''' integers. | ||
+ | <br> | ||
+ | This example exclusively using STL library '''''<list>''''' and '''''recursion'''''. | ||
+ | <br> | ||
+ | '''''Approach:''''' | ||
+ | <br> | ||
+ | '''''Step 1:''''' Take out the first value of the list. | ||
+ | <br> | ||
+ | '''''Step 2:''''' Reverse the rest of the list recursively. | ||
+ | <br> | ||
+ | '''''Step 3:''''' Append the removed value to the end of the reversed rest of the list. | ||
+ | <syntaxhighlight lang="c"> | ||
+ | void listReverse(list<int>& my_list) | ||
+ | { | ||
+ | if (my_list.size() <= 1) return; // base case | ||
+ | |||
+ | int first = my_list.front(); | ||
+ | my_list.erase(my_list.begin()); // remove the first element | ||
+ | |||
+ | listReverse(my_list); // reverse the rest of the list | ||
+ | my_list.push_back(first); // append the first element at the end | ||
+ | } | ||
+ | </syntaxhighlight> | ||
+ | <BR/> |
Latest revision as of 23:52, 22 May 2018
A linked list is like an array that can grow without restriction of a fixed-size array. The disadvantage is that unlike an array that we can access by an index, we have to iterate through the elements of the list. This is because unlike an array which has contiguous memory, linked list memory is usually scattered.
To show a picture, an array looks like this :
[0] [1] [2] [3] ...
A linked list looks like this :
head --> [0] --> [1] --> [2] --> [3] --> [NULL]
Each element of the linked list can be scattered in memory and a pointer is used to indicate where in memory you can find the next element. If the next element doesn't exist, a NULL pointer is used to mark the end.
Contents
Singly Linked List
Structure
typedef struct linked_list_node {
struct linked_list_node *next;
int data;
} linked_list_t;
Observations :
-
linked_list_t
is used such that when we want to declare the linked-list node, we can just uselinked_list_t node
rather thanstruct linked_list_node node;
- For the
*next;
linked-list pointer, we have to explicitly use astruct
keyword because at that point in time, thelinked_list_t
has not been declared.
- For the
- The
int data;
is the actual data of a node, which could bevoid*
too.
Allocation and Adding elements
#include <stdlib.h> /* malloc() */
/* Assume this is a source file, such as linked_list.c */
/* g for "global" variable of this file, and static for "private variable" of this file */
static linked_list_t *g_head = NULL;
void ll_allocate_head(int n)
{
g_head = malloc(sizeof(*g_head));
g_head->data = n;
g_head->next = NULL;
}
void ll_add_to_beg(int n)
{
if (NULL == g_head) {
ll_allocate_head(n);
}
else {
linked_list_t *new_elm = malloc(sizeof(linked_list_t));
/* Copy the data, and set this node's next to the older head */
new_elm->next = g_head;
new_elm->data = n;
/* Head becomes this element since we wanted to add to beginning */
g_head = new_elm;
}
}
void ll_add_to_end(int n)
{
if (NULL == g_head) {
ll_allocate_head(n);
}
else {
/* Need to get to the tail first */
linked_list_t *tail = g_head;
while(tail->next != NULL) {
tail = tail->next;
}
linked_list_t *new_elm = malloc(sizeof(linked_list_t));
new_elm->next = NULL;
new_elm->data = n;
/* Simply add new element to the tail */
tail->next = new_elm;
}
}
List Reversal
#include <stdlib.h> /* malloc() */
/*Function to reverse a singly linked list by iterating through the list*/
void ll_reverse(linked_list_t** data)
{
linked_list_t* prev = NULL; /*previous node is made NULL*/
linked_list_t* g_head= *data; /*data is assigned to head node*/
linked_list_t* next;
while (g_head)
{
next = g_head->next;
g_head->next = prev;
prev = g_head;
g_head= next;
}
*data= prev;
}
Loop in the List
#include <stdlib.h> /* malloc() */
/*Function to detect a loop in a singly linked list by iterating through the list by using two pointers
Slow pointer -> steps through each node
Fast pointer -> Skips every other node
*/
bool ll_loop(linked_list_t* head)
{
linked_list_t *slow= head, *fast = head;
while((slow!=NULL)&&(fast->next!=NULL)&&(fast!=NULL))//checking to see if the current position or the
{ //successive position is pointing to a NULL.
slow = slow-> next; //slow pointer
fast = fast->next->next; //fast pointer
if(slow==fast){ //comparing to see if the slow and fast pointers meet at a node.
return TRUE; //return true if the loop exists
}
}
return FALSE; //return false if the loop doesnt exists.
}
Removing duplicate elements
#include <stdlib.h> /* malloc() */
/* Assume this is a source file, such as linked_list.c */
/* g for "global" variable of this file, and static for "private variable" of this file */
static linked_list_t *g_head = NULL;
void remove_dups(linked_list_t* head){ //we are never deleting the head node
linked_list_t* current = head; //current node
linked_list_t *pointer1, *duplicate;
while(current->next != NULL){//traversing the list pointed by current
pointer1 = current;// the current node is copied into pointer1
while(pointer1->next != NULL){// traversing the list pointed by pointer1
if(pointer1->next->data == current->data){ //Checking for duplicates by comparing the current data and pointer1 data of next node
duplicate = pointer1->next;// copy the address of pointer1 node (which contains duplicate data) into duplicate
pointer1->next = pointer1->next->next;//placing the new address i.e. the next node address into pointer to which it will be pointing next
free(duplicate);//free the duplicate node (which contains duplicate data)
}
pointer1 = pointer1->next;//move to the next node
}
current = current->next;//current pointing to next node
}
}
}
Palindrome
#include <stdlib.h> /* malloc() */
/* Assume this is a source file, such as linked_list.c */
/* g for "global" variable of this file, and static for "private variable" of this file */
static linked_list_t *g_head = NULL;
bool isPalindrome(linked_list_t *head){
linked_list_t *reverse = reverse(head);// calling function to reverse the list
return checkPalindrome(head,reverse);// calling function to check if the list is Palindrome
}
linked_list_t* reverse(linked_list_t *head1){
linked_list_t *temp = NULL;
while(head1->next != NULL){
linked_list_t *new_reverse_node = (linked_list_t*)malloc(sizeof(linked_list_t));// new node create to copy the current list in reverse order
new_reverse_node->data = head1->data;// copy head data into new node
new_reverse_node->next = temp;//reversing the list by making the first node the last node
temp = new_reverse_node;
head1 = head1->next;//traverse till the end of the list
}
return temp;
}
bool checkPalindrome(linked_list_t *list1, linked_list_t *list2){
while(list1->next != NULL && list2->next != NULL){
if(list1->data != list2->data){
return false;
}
list1 = list1->next;
list2 = list2->next;
}
if(list1->next == NULL && list2->next == NULL){
return true;
}
}
Doubly Linked List
Let's elaborate on our linked list such that we have the next and the previous links. We will have the added benefit of going backwards from an element at the cost of the memory requirement of an extra pointer along with more code to deal with this extra pointer.
typedef struct linked_list_node {
struct linked_list_node *next; /*next node*/
struct linked_list_node* prev; /*previous node*/
int data;
} linked_list_t;
/* Assume this is a source file, such as linked_list.c */
/* g for "global" variable of this file, and static for "private variable" of this file */
static linked_list_t *g_head = NULL;
/*new node is created and a pointer is returned */
linked_list_t *create_new_node(int n ) {
linked_list_t *new_node
= malloc(sizeof(linked_list_t)); /*creating a new node*/
new_node->data = n; /*assigning input to data*/
new_node->prev = NULL; /*previous and next links are initialized to NULL*/
new_node->next = NULL;
return new_node; /*returning a pointer*/
}
/*Inserting node at head */
void insert_at_head(int n) {
linked_list_t* new_node = create_new_node(n); /*creating a new node*/
if(g_head == NULL) { /*condition to check if the head node is empty*/
g_head = new_node;
return;
}
g_head->prev = new_node; /*assigning new node to head node */
new_node->next = g_head;
g_head = new_node;
}
/*to insert a node at tail*/
void insert_at_tail(int n) {
linked_list_t* temp = g_head;
linked_list_t* new_node = create_new_node(n); //creating a new node
if(g_head == NULL) {
g_head = new_node;
return;
}
while(temp->next != NULL) temp = temp->next; //last node
temp->next = new_node;
new_node->prev = temp;
}
Delete a node in a linked list
typedef struct linked_list_node {
struct linked_list_node *next; /*next node*/
int data;
} linked_list_t;
void delete_node(linked_list_t *g_head, linked_list_t *N)
{
/* to delete head node */
if(g_head == N)
{
if(g_head->next == NULL)
{
return;
}
/* Copy next node data to head node */
g_head->data = g_head->next->data;
/* copy address of next node to N*/
N = g_head->next;
/* delete next node */
g_head->next = g_head->next->next;
free(N);
return;
}
/* to delete a node other than the first(head) node */
/*previous node */
linked_list_t *prev = g_head;
while(prev->next != NULL && prev->next != N)
prev = prev->next;
/*check if prev node exists */
if(prev->next == NULL)
{
return;
}
/*Delete that node from Linked List
prev->next = prev->next->next;
free(N);
return;
}
Make List unique using STL and recursion
The task - given a list of n integers in a list, remove all the duplicate values so that what remains is a list of unique values.
This example exclusively makes use of STL Library <list> and recursion.
Approach: First define function member_of that checks if a value x' is present in the list.
bool member_of(const int value, const list<int>& my_list, list<int>::const_iterator it)
{
if (it == my_list.end())
return false;
return (*it == value) || member_of(value, my_list, ++it);
}
Now, take out the first value. Make the rest of the list unique. Then if the value we took out is not in the rest of the list, put it back. Otherwise, leave it out.
void isListUnique(list<int>& alist)
{
if (alist.size() <= 1) return; // base case
int first = alist.front();
alist.erase(alist.begin()); // remove the first element
isListUnique(alist); // make the rest of the list unique
if (!member_of(first, alist, alist.begin()))
{
alist.push_front(first); // put back the first element
}
}
Reverse a linked list using STL and recursion
Task - Reverse the values of a list of n integers.
This example exclusively using STL library <list> and recursion.
Approach:
Step 1: Take out the first value of the list.
Step 2: Reverse the rest of the list recursively.
Step 3: Append the removed value to the end of the reversed rest of the list.
void listReverse(list<int>& my_list)
{
if (my_list.size() <= 1) return; // base case
int first = my_list.front();
my_list.erase(my_list.begin()); // remove the first element
listReverse(my_list); // reverse the rest of the list
my_list.push_back(first); // append the first element at the end
}