Difference between revisions of "Interview Preparation Pointers"
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Pointer 20 | Pointer 20 | ||
</pre> | </pre> | ||
| + | |||
| + | '''Malloc''' | ||
| + | The Malloc function dynamically allocates memory when required. The function allocates size of byte of memory and returns a pointer to the first byte of NULL. | ||
| + | <pre> | ||
| + | |||
| + | Syntax: | ||
| + | pointer = (type)malloc(size in bytes); | ||
| + | |||
| + | Code: | ||
| + | |||
| + | int* p; //Declare pointer | ||
| + | p = (int*)malloc(sizeof(int)); // Pointer equal to pointer type int that contain memory address space of int | ||
| + | *p = 5; // Finally pointer points to location containing value 5 | ||
| + | </pre> | ||
Revision as of 15:02, 17 December 2016
Pointers : A pointer is a variable who's value is address of some other variable i.e. it can be address of some memory location.
<varaible_type> *<name>
eg :
int *pointer_to_integer
The above example , we have declared a pointer to a variable (pointer_to_integer), the variable stores the address of an integer .
Implementation of Pointer :
Code:
#include <stdio.h>
int main(void) {
int var = 20;
int *p;
p = &var;
printf("Pointer %d\n",var);
printf("Pointer %d\n",&var); // Prints the address of the varaible (var)
printf("Pointer %d\n",p);
printf("Pointer %d\n",*p); // Prints the value that (p) points to
return 0;
}
Output :
Pointer 20
Pointer 1809844068
Pointer 1809844068
Pointer 20
Malloc
The Malloc function dynamically allocates memory when required. The function allocates size of byte of memory and returns a pointer to the first byte of NULL.
Syntax: pointer = (type)malloc(size in bytes); Code: int* p; //Declare pointer p = (int*)malloc(sizeof(int)); // Pointer equal to pointer type int that contain memory address space of int *p = 5; // Finally pointer points to location containing value 5